15w^2+17w-4=0

Solution for 15w^2+17w-4=0 equation:

15w^2+17w-4=0

a = 15; b = 17; c = -4;
Δ = b2-4ac
Δ = 172-4·15·(-4)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*15}=\frac{-40}{30}
=-1+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*15}=\frac{6}{30}
=1/5
$